document.write( "Question 956322: log₃ 6 + log₃ (3x + 1) = 21 \n" ); document.write( "
Algebra.Com's Answer #584246 by Theo(13342)\"\" \"About 
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log3(6) + log3(3x+1) = 21\r
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\n" ); document.write( "\n" ); document.write( "log3(6) + log(3x+1) is the same as log3(6 * (3x+1)) which is the same as:\r
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\n" ); document.write( "\n" ); document.write( "log3(18x + 6)\r
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\n" ); document.write( "\n" ); document.write( "your equation becomes log3(18x+6) = 21\r
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\n" ); document.write( "\n" ); document.write( "this is true if and only if 3^21 = 18x + 6\r
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\n" ); document.write( "\n" ); document.write( "subtract 6 from both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "3^21 - 6 = 18x\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by 18 to get:\r
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\n" ); document.write( "\n" ); document.write( "(3^21 - 6) / 18 = x\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = 581130733.2\r
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\n" ); document.write( "\n" ); document.write( "that's your solution.\r
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\n" ); document.write( "\n" ); document.write( "replace x with 581130733.2 in the original equation to get:\r
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\n" ); document.write( "\n" ); document.write( "log3(6) + log3(3*581130733.2+1) = 21\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "log3(6) + log3(1743392201) = 21\r
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\n" ); document.write( "\n" ); document.write( "convert log base 3 to log base 10 using the conversion formula of log3(a) = log10(a)/log10(3) which can also be shown as log(a)/log(3).\r
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\n" ); document.write( "\n" ); document.write( "your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "log(6)/log(3) + log(1743392201)/log(3) = 21\r
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\n" ); document.write( "\n" ); document.write( "use your calculator log function to evaluate this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "21 = 21\r
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\n" ); document.write( "\n" ); document.write( "this conforms your solution is correct.\r
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