document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956211>Question 956211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has two solutions. One is 40% alcohol, and the other is pure alcohol. How much of each solution should be mixed together to make 1.6 liters of a solution that is 52% alcohol?\r<BR>\n" );
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document.write( "I have tried x + y= 1.6   x=1.6-y \r<BR>\n" );
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document.write( "Also using grids. \r<BR>\n" );
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document.write( "Came up with <BR>\n" );
document.write( "0.40(1.6-y) + 1.00y= .832<BR>\n" );
document.write( "0.64-0.40y + 1.00y =.832<BR>\n" );
document.write( "0.64 +0.6y= .832<BR>\n" );
document.write( "0.6y= 1.3<BR>\n" );
document.write( "y=2.16\r<BR>\n" );
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document.write( "I feel I am doing something very wrong. Help is greatly appreciated.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584189 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584189\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has two solutions. One is 40% alcohol, and the other is pure alcohol. How much of each solution should be mixed together to make 1.6 liters of a solution that is 52% alcohol?<BR>\n" );
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document.write( "let x=amt of 40% alcohol to mix<BR>\n" );
document.write( "1.6-x=amt of pure(100%) alcohol to mix<BR>\n" );
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document.write( "40%x+100%(1.6-x)=52%*1.6<BR>\n" );
document.write( ".40x+1.6-x=0.832<BR>\n" );
document.write( ".60x=0.768<BR>\n" );
document.write( "x=1.28<BR>\n" );
document.write( "1.6-x=0.32<BR>\n" );
document.write( "amt of 40% alcohol to mix=1.28 liters<BR>\n" );
document.write( "amt of pure(100%) alcohol to mix=0.32 liters<BR>\n" );
document.write( "note: your setup is ok, you just added instead of subtracting in the 4th step. </SPAN>\n" );
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