document.write( "Question 956201: what comes after 3.5,13,41.5,127, , , , \n" ); document.write( "
Algebra.Com's Answer #584188 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "We try to find a multiplier, m, and an adder, a\r\n" );
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document.write( " 3.5m+a =  13\r\n" );
document.write( "  13m+a =  41.5\r\n" );
document.write( "41.5m+a = 127\r\n" );
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document.write( "Removing the decimals by multiplying each through by 2\r\n" );
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document.write( "  7m+2a = 26\r\n" );
document.write( " 26m+2a = 83\r\n" );
document.write( " 83m+2a = 254\r\n" );
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document.write( "Solve the first for 2a\r\n" );
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document.write( "    2a = 26-7m\r\n" );
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document.write( "Substitute in the second\r\n" );
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document.write( " 26m+26-7m = 83\r\n" );
document.write( "    19m+26 = 83\r\n" );
document.write( "       19m = 57\r\n" );
document.write( "         m = 3\r\n" );
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document.write( "Substitute in \r\n" );
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document.write( "   2a = 26-7m\r\n" );
document.write( "   2a = 26-7(3)\r\n" );
document.write( "   2a = 26-21\r\n" );
document.write( "   2a = 5\r\n" );
document.write( "    a = 2.5\r\n" );
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document.write( "See if those values satisfy\r\n" );
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document.write( "       83m+2a = 254\r\n" );
document.write( " 83(3)+2(2.5) = 254\r\n" );
document.write( "      249 + 5 = 254\r\n" );
document.write( "          254 = 254\r\n" );
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document.write( "Yes they do!\r\n" );
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document.write( "So substituting in\r\n" );
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document.write( " 3.5m+a =  13\r\n" );
document.write( "  13m+a =  41.5\r\n" );
document.write( "41.5m+a = 127\r\n" );
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document.write( "  3.5(3)+2.5 =  10.5+2.5 = 13\r\n" );
document.write( "   13(3)+2.5 =    39+2.5 = 41.5\r\n" );
document.write( " 41.5(3)+2.5 = 124.5+2.5 = 127  \r\n" );
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document.write( "Continuing the pattern:\r\n" );
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document.write( "   127(3)+2.5 =    381+2.5 =  383.5\r\n" );
document.write( " 383.5(3)+2.5 = 1150.5+2.5 = 1153\r\n" );
document.write( "  1153(3)+2.5 =   3459+2.5 = 3461.5      \r\n" );
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document.write( "Edwin

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