document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956110>Question 956110</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 16. Three times the larger number decreased by the smaller number is 72. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584130 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584130\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=the larger number; y=the smaller number<BR>\n" );
document.write( "x+y=16<BR>\n" );
document.write( "x=16-y<BR>\n" );
document.write( "3x-y=72 Substitute for x<BR>\n" );
document.write( "3(16-y)-y=72<BR>\n" );
document.write( "48-3y-y=72 Subtract 48 from each side.<BR>\n" );
document.write( "-4y=24 Divide each side by -4<BR>\n" );
document.write( "y=-6 ANSWER 1:The smaller number is -6.<BR>\n" );
document.write( "x=16-y=16-(-6)=22 ANSWER 2: The larger number is 22.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "3x-y=72<BR>\n" );
document.write( "3(22)-(-6)=72<BR>\n" );
document.write( "66-(-6)=72<BR>\n" );
document.write( "72=72 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );