document.write( "Question 956124: Mrs. Garrison has $15,000 to invest. She invested part of it at a bank for 6% annual interest and another at 7% annual intres. If she earned $980 in interest, how much did she invest each rate? Show your work. \n" ); document.write( "
Algebra.Com's Answer #584116 by macston(5194)![]() ![]() You can put this solution on YOUR website! x=amount at 6%; y=amount at 7% \n" ); document.write( "x+y=$15000 \n" ); document.write( "x=$15000-y \n" ); document.write( "0.06x+0.07y=$980 Substitute for x. \n" ); document.write( "0.06($15000-y)+0.07y=$980 \n" ); document.write( "$900-0.06y+0.07y=$980 Subtract $900 from each side. \n" ); document.write( "0.01y=$80 Divide each side by 0.01 \n" ); document.write( "y=$8000 ANSWER 1: $8000 was invested at 7%. \n" ); document.write( "x=$15000-y=$15000-$8000=$7000 ANSWER 2: $7000 was invested at 6%. \n" ); document.write( "CHECK: \n" ); document.write( "0.06x+0.07y=$980 \n" ); document.write( "0.06($7000)+0.07($8000)=$980 \n" ); document.write( "$420+$560=$980 \n" ); document.write( "$980=$980 \n" ); document.write( " |