document.write( "Question 956109: Please help me with this problem:The floor of a cabin is shaped like a rectangle. It has a surface area of 288 square feet. If the perimeter of the floor is 68 feet, what is the length of the floor?
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Algebra.Com's Answer #584111 by macston(5194)![]() ![]() You can put this solution on YOUR website! L=length;W=width; P=perimeter=68ft; A=area=288 sq ft \n" ); document.write( "A=L*W \n" ); document.write( "L=A/W \n" ); document.write( "P=2(L+W) Substitute for L \n" ); document.write( "68ft=2((A/W)+W) Divide each side by 2 \n" ); document.write( "34ft=(288sqft/W)+W Subtract W from each side. \n" ); document.write( "34ft-W=288sqft/W Multiply each side by W \n" ); document.write( " \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The width is 16ft or 18ft and length is the other. \n" ); document.write( "ANSWER: The dimensions are 18 feet by 16 feet. \n" ); document.write( "CHECK: \n" ); document.write( "P=2(L+W) \n" ); document.write( "68ft=2(18ft+16ft) \n" ); document.write( "68ft=2(34ft) \n" ); document.write( "68ft=68ft \n" ); document.write( "A=LW \n" ); document.write( "288 sq ft=(18ft)(16ft) \n" ); document.write( "288 sq ft=288 sq ft \n" ); document.write( " |