document.write( "Question 955754: http://jasper.kaptest.com/content/media/00/124700.11.25cbb913-01d3-4258-af2b-5415d367e71e.png\r
\n" ); document.write( "\n" ); document.write( "In the figure above, AC is tangent at point B to the circle centered at O. DFis parallel to AC . If DF=6sqrt 3 and the circumference of the circle is 12π, what is the probability that a point randomly selected from the interior of the circle will fall within the shaded region?\r
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Algebra.Com's Answer #584096 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
From the circumference,
\n" ); document.write( "\"12pi=pi%2A%282%2AOD%29\"
\n" ); document.write( "\"OD=6\"
\n" ); document.write( "and since \"DE=%281%2F2%29DF=3sqrt%283%29\"
\n" ); document.write( "and
\n" ); document.write( "\"sin%28theta%29=DE%2FOD\"
\n" ); document.write( "\"sin%28theta%29=%283sqrt%283%29%29%2F6\"
\n" ); document.write( "\"sin%28theta%29=sqrt%283%29%2F2\"
\n" ); document.write( "\"theta=60\"
\n" ); document.write( "So the shaded region takes up 120 degrees of the 360 degree circle total.
\n" ); document.write( "\"P=120%2F360=1%2F3\"
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