document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955943>Question 955943</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Elizabeth drove half the distance of a trip at 35 mph. At what speed would she have to drive for the rest of the distance so that the average speed for the entire trip would be 52 mph?\r<BR>\n" );
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document.write( "Help please! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584081 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Elizabeth drove half the distance of a trip at 35 mph. At what speed would she have to drive for the rest of the distance so that the average speed for the entire trip would be 52 mph?<BR>\n" );
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document.write( "d = 1/2 the total distance<BR>\n" );
document.write( "r = speed of the 2nd half<BR>\n" );
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document.write( "d/35 + d/r = 2d/52<BR>\n" );
document.write( "1/35 + 1/r = 1/26<BR>\n" );
document.write( "(r + 35)/35r = 1/26<BR>\n" );
document.write( "r+35 = 35r/26<BR>\n" );
document.write( "26r + 910 = 35r<BR>\n" );
document.write( "9r = 910<BR>\n" );
document.write( "r = 101.111...  mi/hr<BR>\n" );
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