document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956007>Question 956007</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a square has the same area as a rectangle whose length is 8 feet more than the side of the square and whose width is 4 feet less than the side of the square.find the side of the square  , i really dont know how to solve it with out the given area<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584025 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584025\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We are given<BR>\n" );
document.write( "area of square = area of rectangle<BR>\n" );
document.write( "let s be the side of the square, then<BR>\n" );
document.write( "s^2 = (s+8)*(s-4)<BR>\n" );
document.write( "s^2 = s^2 +4s -32<BR>\n" );
document.write( "subtract s^2 from both sides of =<BR>\n" );
document.write( "0 = 4s -32<BR>\n" );
document.write( "add 32 to both sides of =<BR>\n" );
document.write( "4s = 32<BR>\n" );
document.write( "s = 8<BR>\n" );
document.write( "The length of a side of the square is 8 feet </SPAN>\n" );
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