document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956005>Question 956005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A fort has food for 160 people for 50 days . After 10 days 20 ppl left the fort . How long the food  last at the same rate for the remaining ppl ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584021 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584021\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A fort has food for 160 people for 50 days . After 10 days 20 ppl left the fort . How long the food  last at the same rate for the remaining ppl ?<BR>\n" );
document.write( "Let x= amount of time the food will last for the remaining people<BR>\n" );
document.write( "The fort has 160*50=8000 people-days worth of food<BR>\n" );
document.write( "In 10 days the fort consumes 160*10=1600 people-days of food leaving (8000-1600)=6400 people-days of food yet to be consumed by (160-20)=140 people<BR>\n" );
document.write( "Sooooo, our equation to solve is:<BR>\n" );
document.write( "140x=6400<BR>\n" );
document.write( "x=45.714 days---amount of time the food will last for the remaining people\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor<BR>\n" );
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