document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955956>Question 955956</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The fence around a rectangular yard requires 260 feet of fencing. The length is 20 less than twice the width. What are the dimensions of the yard?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583998 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=perimeter=260ft; W=width; L=length=2W-20<BR>\n" );
document.write( "P=2(L+W) Substitute for L<BR>\n" );
document.write( "260ft=2(2W-20+W)<BR>\n" );
document.write( "260 ft=2(3W-20ft)<BR>\n" );
document.write( "260ft=6W-40ft Add 40ft to each side.<BR>\n" );
document.write( "300ft=6W Divide each side by 6.<BR>\n" );
document.write( "50ft=W ANSWER 1: The width is 50 feet.<BR>\n" );
document.write( "L=2W-20ft=2(50ft)-20ft=100ft-20ft=80ft ANSWER 2: The length is 80 feet.<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "260ft=2(80ft+50ft)<BR>\n" );
document.write( "260ft=2(130ft)<BR>\n" );
document.write( "260ft=260ft \r<BR>\n" );
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