document.write( "Question 955924: A survey was conducted to measure the number of hours per week adults spend on home computers. In the survey, the number of hours was normally distributed, with a mean of 8 hours and a standard deviation of 1 hour. A survey participant is randomly selected. Find the probability that the hours spent on the home computer by the participant are between 5.5 and 9.5 hours per week.
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Algebra.Com's Answer #583980 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A survey was conducted to measure the number of hours per week adults spend on home computers. In the survey, the number of hours was normally distributed, with a mean of 8 hours and a standard deviation of 1 hour. A survey participant is randomly selected. Find the probability that the hours spent on the home computer by the participant are between 5.5 and 9.5 hours per week. \n" ); document.write( "---------------------- \n" ); document.write( "z(5.5) = (5.5-8)/1 = -2.5 \n" ); document.write( "z(9.5) = (9.5-8)/1 = 1.5 \n" ); document.write( "---- \n" ); document.write( "P(5.5< x < 9.5) = P(-2.5< z < 1.5) = normalcdf(-2.5,1.5) = 0.2417 \n" ); document.write( "--------------- \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " \n" ); document.write( " |