document.write( "Question 955922:
\n" ); document.write( "18. Mark walks 3 miles to the house of a friend and returns home on a bike. He averages 5 mph faster when cycling than walking, and the total time for both trips is 2 hours. Find his walking speed.
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Algebra.Com's Answer #583978 by stanbon(75887)\"\" \"About 
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Mark walks 3 miles to the house of a friend and returns home on a bike. He averages 5 mph faster when cycling than walking, and the total time for both trips is 2 hours. Find his walking speed.
\n" ); document.write( "Walking DATA::
\n" ); document.write( "dist = 3 miles ; rate = x mph ; time = d/r = 3/x hrs
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\n" ); document.write( "Bike DATA:
\n" ); document.write( "dist = 3 miles ; rate = (x+5) mph ; time = 3/(x+5) hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "time + time = 2 hrs
\n" ); document.write( "3/x + 3/(x+5) = 2
\n" ); document.write( "3(x+5) + 3x = 2x(x+5)
\n" ); document.write( "3x + 15 = 2x^2 + 10x
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\n" ); document.write( "2x^2 + 7x - 15 = 0
\n" ); document.write( "2x^2 + 10x-3x - 15 = 0
\n" ); document.write( "2x(x+5) - 3(x+5) = 0
\n" ); document.write( "(x+5)(2x-3) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 3/2 mph (walking rate)
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\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.
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