document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955829>Question 955829</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ship left port A with a speed of 40 mph. In 1 hour and 15 minutes, a second ship left the port with a speed of 60 mph. In how many hours and at what distance from port A will the second ship catch up with the first one? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583909 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A ship left port A with a speed of 40 mph. In 1 hour and 15 minutes, a second ship left the port with a speed of 60 mph. In how many hours and at what distance from port A will the second ship catch up with the first one?<BR>\n" );
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document.write( "1st ship DATA:<BR>\n" );
document.write( "rate = 40 mph ; time = x hrs ; distance = 40x miles<BR>\n" );
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document.write( "2nd ship DATA:<BR>\n" );
document.write( "rate = 60 mph ; time = (x-(5/4)) hrs ; distance = 60(x-(5/4)) miles<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "dist = dist<BR>\n" );
document.write( "40x = 60x - 75<BR>\n" );
document.write( "20x = 75<BR>\n" );
document.write( "x = 15/4 hrs<BR>\n" );
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document.write( "Dist from 1st port:: 40x = 40(15/4)  = 150 miles<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );