document.write( "Question 955829: A ship left port A with a speed of 40 mph. In 1 hour and 15 minutes, a second ship left the port with a speed of 60 mph. In how many hours and at what distance from port A will the second ship catch up with the first one? \n" ); document.write( "

Algebra.Com's Answer #583907 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
In $\"+1.25+\"$ hrs, the 1st ship travels:
\n" ); document.write( " $\"+d%5B1%5D+=+40%2A1.25+\"$
\n" ); document.write( " $\"+d%5B1%5D+=+50+\"$ mi
\n" ); document.write( "-----------------
\n" ); document.write( "Start a stopwatch when 2nd ship leaves
\n" ); document.write( "Let $\"+t+\"$ = time in hrs when 2nd ship
\n" ); document.write( "catches the 1st ship
\n" ); document.write( "Let $\"+d+\"$ = distance from port A when
\n" ); document.write( "2nd ship catches 1st ship
\n" ); document.write( "-----------------------
\n" ); document.write( "Equation for 1st ship:
\n" ); document.write( "(1) $\"+d+-+50+=+40t+\"$
\n" ); document.write( "Equation for 2nd ship:
\n" ); document.write( "(2) $\"+d+=+60t+\"$
\n" ); document.write( "----------------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) $\"+60t+-+50+=+40t+\"$
\n" ); document.write( "(1) $\"+20t+=+50+\"$
\n" ); document.write( "(1) $\"+t+=+2.5+\"$
\n" ); document.write( "------------------
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+d+=+60%2A2.5+\"$
\n" ); document.write( "(2) $\"+d+=+150+\"$
\n" ); document.write( "150 mi from port A, 2nd ship catches the 1st ship
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+d+-+50+=+40t+\"$
\n" ); document.write( "(1) $\"+150+-+50+=+40%2A2.5+\"$
\n" ); document.write( "(1) $\"+100+=+100+\"$
\n" ); document.write( "OK\r
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