document.write( "Question 955823: Two years ago, John was 3 times as old as Bob. In 5 years time, John will be twice as old as Bob. Find John's present age \n" ); document.write( "
Algebra.Com's Answer #583894 by macston(5194)![]() ![]() You can put this solution on YOUR website! Two years ago, John was 3 times as old as Bob. In 5 years time, John will be twice as old as Bob. Find John's present age \n" ); document.write( "J=John; B=Bob \n" ); document.write( "J-2=3(B-2) \n" ); document.write( "J-2=3B-6 \n" ); document.write( "J=3B-4 \n" ); document.write( "J+5=2(B+5) Substitute for J \n" ); document.write( "3B-4+5=2B+10 Subtract 2B from each side. \n" ); document.write( "B+1=10 Subtract 1 from each side. \n" ); document.write( "B=9 ANSWER 1: Bob is 9 years old. \n" ); document.write( "J=3B-4=3(9)-4=27-4=23 ANSWER 2: John is 23 years old. \n" ); document.write( "CHECK: \n" ); document.write( "J+5=2(B+5) \n" ); document.write( "23+5=2(9+5) \n" ); document.write( "28=2(14) \n" ); document.write( "28=28 \n" ); document.write( " \n" ); document.write( " |