document.write( "Question 955823: Two years ago, John was 3 times as old as Bob. In 5 years time, John will be twice as old as Bob. Find John's present age \n" ); document.write( "
Algebra.Com's Answer #583894 by macston(5194)\"\" \"About 
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Two years ago, John was 3 times as old as Bob. In 5 years time, John will be twice as old as Bob. Find John's present age
\n" ); document.write( "J=John; B=Bob
\n" ); document.write( "J-2=3(B-2)
\n" ); document.write( "J-2=3B-6
\n" ); document.write( "J=3B-4
\n" ); document.write( "J+5=2(B+5) Substitute for J
\n" ); document.write( "3B-4+5=2B+10 Subtract 2B from each side.
\n" ); document.write( "B+1=10 Subtract 1 from each side.
\n" ); document.write( "B=9 ANSWER 1: Bob is 9 years old.
\n" ); document.write( "J=3B-4=3(9)-4=27-4=23 ANSWER 2: John is 23 years old.
\n" ); document.write( "CHECK:
\n" ); document.write( "J+5=2(B+5)
\n" ); document.write( "23+5=2(9+5)
\n" ); document.write( "28=2(14)
\n" ); document.write( "28=28
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