document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955661>Question 955661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A company management team knows that, in a given quarter, the mean of earnings of firms in their industry is $200,000 with an industry standard deviation of $80,000. Assume a normal distribution. What is the probability that a company makes more than $300,000? Round your answer to 2 decimal places.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583839 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A company management team knows that, in a given quarter, the mean of earnings of firms in their industry is $200,000 with an industry standard deviation of $80,000. Assume a normal distribution. What is the probability that a company makes more than $300,000? <BR>\n" );
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document.write( "z(300000) = (300000-200000)/80000 = 100/80 = 5/4<BR>\n" );
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document.write( "P(x > 300000) = P(z > 5/4) = normalcdf(5/4,100) = 0.1057<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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