document.write( "Question 955652: Suppose $20,000 is invested into an account where interest is compounded semiannually. After 30 years the balance is $231,165.\r
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document.write( "What was the interest rate as a percent?\r
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document.write( "Round the answer to the nearest hundredth of a percent.
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Algebra.Com's Answer #583827 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Suppose $20,000 is invested into an account where interest is compounded semiannually. After 30 years the balance is $231,165. \n" ); document.write( "What was the interest rate as a percent? \n" ); document.write( "Round the answer to the nearest hundredth of a percent. \n" ); document.write( "*** \n" ); document.write( "Compound Interest Formula: A=P(1+r/n)^nt, P=initial investment, r=interest rate, n=number of compounding periods per year, A=amt after t-years \n" ); document.write( "For given problem: \n" ); document.write( "P=20000 \n" ); document.write( "r=interest rate(to be determined) \n" ); document.write( "n=2 \n" ); document.write( "t=30 \n" ); document.write( "A=amt after 30 yrs \n" ); document.write( "... \n" ); document.write( "231165=20000(1+r/2)^2*30 \n" ); document.write( "231165/20000=(1+r/2)^60 \n" ); document.write( "11.5583=(1+r/2)^60 \n" ); document.write( "raise both sides to the 1/60th power \n" ); document.write( "1.04163=1+r/2 \n" ); document.write( "r/2=1.04163-1=.04163 \n" ); document.write( "r=.02082=2.082% \n" ); document.write( "What was the interest rate as a percent? 2.082% \n" ); document.write( " |