document.write( "Question 955594: -2 cos 2x = sqrt3 \n" ); document.write( "
Algebra.Com's Answer #583790 by lwsshak3(11628)\"\" \"About 
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For interval:(0, 2π)
\n" ); document.write( "-2 cos 2x = sqrt3
\n" ); document.write( "cos(2x)=-√3/2
\n" ); document.write( "2x=5π/6, 7π/6 (In quadrants II and III where cos<0)
\n" ); document.write( "x=5π/12, 7π/12
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