document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955599>Question 955599</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 2% acid solution must be mixed witha 10% acid solution to get 6L of a 6% solution.<BR>\n" );
document.write( "How many liters of a 2% solution are needed </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583787 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a 2% acid solution must be mixed witha 10% acid solution to get 6L of a 6% solution.<BR>\n" );
document.write( "How many liters of a 2% solution are needed<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=amt of 2% solution needed<BR>\n" );
document.write( "6-x=amount 10% solution to mix<BR>\n" );
document.write( "2%x+10%(6-x)=6%*6<BR>\n" );
document.write( ".02x+.60-.10x=.36<BR>\n" );
document.write( ".08x=.24<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "amt of 2% solution needed=3L </SPAN>\n" );
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