document.write( "Question 955543: if man 1 fills a tank in 60min's and man 2 fills in 30min's and man 3 fills in 20mins how long if they fill together please break down as simple as possible for me to understand \n" ); document.write( "
Algebra.Com's Answer #583748 by ptaylor(2198)\"\" \"About 
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Let x= amount of time needed to fill tank if they work together
\n" ); document.write( "Together the three men fill at the rate of 1/x of the tank per min\r
\n" ); document.write( "\n" ); document.write( "man1 fills at the rate of 1/60 of a tank per min
\n" ); document.write( "man2 fills at the rate of 1/30 of a tank per min
\n" ); document.write( "man3 fills at the rate of 1/20 of a tank per min
\n" ); document.write( "sooooo
\n" ); document.write( "1/60 + 1/30 + 1/20= 1/x. multiply each term by 60x
\n" ); document.write( "x+2x+3x=60
\n" ); document.write( "6x=60
\n" ); document.write( "x=10 min---time needed if they work together
\n" ); document.write( "CK
\n" ); document.write( "In 10 min, man1 fills 10/60=1/6 of the tank
\n" ); document.write( "In 10min, man2 fills 10/30=1/3 of the tank
\n" ); document.write( "In 10 min, man3 fills 10/20=1/2 of the tank
\n" ); document.write( "Now 1/6 +1/3+1/2 should add up to one tank and they do:)
\n" ); document.write( "Hope this helps---ptaylor
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