document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955543>Question 955543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if man 1 fills a tank in 60min's and man 2 fills in 30min's and man 3 fills in 20mins how long if they fill together please break down as simple as possible for me to understand </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583747 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Man1 fills 1 tank/60 minutes=1/60 tank per minute. We will convert the other fractions to this denominator to add.<BR>\n" );
document.write( "Man2 fills 1 tank/30 minutes=1/30 tank per minute.1/30 tank/minute(2/2)=2/60 tank/minute.<BR>\n" );
document.write( "Man3 fills 1 tank/20 minutes=1/20 tank per minute.1/20 tank/minute(3/3)=3/60 tank/minute.<BR>\n" );
document.write( "Together:<BR>\n" );
document.write( "Man1+Man2+Man3=1/60 tank/minute+2/60 tank/minute+3/60 tank /minute=6/60 tank/minute=1/10 tank/minute.<BR>\n" );
document.write( "To fill 1 tank at 1/10 tank/minute=(1tank)/(1/10tank/min)=10 minutes<BR>\n" );
document.write( "The three together can fill the tank in ten minutes. </SPAN>\n" );
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