document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955515>Question 955515</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On the first part of a road trip to Batangas travelling on the highway, Kelly averages 60 kph. On the rest of the roadtrip, which was 10 kilometers longer than the first part, she averaged 50 kph. Find the total distance to Batangas if the second part of the trip took 30 minutes more than the first.\r<BR>\n" );
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document.write( "Help please! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583734 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We are given two formulas for rate * time = distance<BR>\n" );
document.write( "60*t = d1, where t is time and d1 is distance for first part of trip<BR>\n" );
document.write( "50 *(t+(1/2)) = d1+10, where (1/2) is half an hour or 30 minutes<BR>\n" );
document.write( "substitute for d1 in second equation<BR>\n" );
document.write( "50 *(t+(1/2)) = (60*t)+10<BR>\n" );
document.write( "50t +25 = 60t +10<BR>\n" );
document.write( "10t = 15<BR>\n" );
document.write( "t = 15/10 = 1.5 hours, therefore<BR>\n" );
document.write( "60*1.5 = 90 kilometers and<BR>\n" );
document.write( "90 + 10 = 100 kilometers and<BR>\n" );
document.write( "90 + 100 = 190 kilometers<BR>\n" );
document.write( "now 190 kilometers is the total distance\r<BR>\n" );
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