document.write( "Question 81497This question is from textbook Glencoe Mathmatics Algebra 2
\n" ); document.write( ": I have to solve this problem:
\n" ); document.write( "2+6e(4x)=19 (the 4x is the exponent)\r
\n" ); document.write( "\n" ); document.write( "I have come up with these possible answers:
\n" ); document.write( ".2604, .5074, .4907, or 2.8333
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Algebra.Com's Answer #58373 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
This is a classic problem of \"undo-ing\" the operations of math in order to solve for x.\r
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\n" ); document.write( "\n" ); document.write( "2+6e(4x)=19 \r
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\n" ); document.write( "\n" ); document.write( "First, you need to \"undo\" the 2 that is added to the term that contains the x. Of course, you do this by subtracting 2 from each side of the equation:\r
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\n" ); document.write( "\n" ); document.write( "\"6e%5E%284x%29+=+17\"\r
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\n" ); document.write( "\n" ); document.write( "Next, you must \"undo\" the 6 that is multiplied times the term containing the x:
\n" ); document.write( "\"e%5E%284x%29+=+17%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "Next, you must \"undo\" the \"e\" raised to the power. The inverse of \"e\" raised to the power is the \"ln\" function, so you must take the \"ln\" of each side:
\n" ); document.write( "\"ln%28e%5E%284x%29%29+=+ln%2817%2F6%29\"
\n" ); document.write( "\"4x=ln%2817%2F6%29\"\r
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\n" ); document.write( "\n" ); document.write( "Finally, undo multiplication of the x times 4 by either dividing both sides by 4 or by multiplying both sides times \"1%2F4\".\r
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\n" ); document.write( "\n" ); document.write( "Final answer \"x=+%28ln%2817%2F6%29%29%2F4+\"
\n" ); document.write( "\"x=+.2604\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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