document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81533>Question 81533</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I need help with the following: The perimeter of a rectangular backyard is 6x+6 yards.  If the width is x yards, find a binomial that represents the length. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58370 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58370\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2W+2L\r<BR>\n" );
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document.write( "Given that P=6x+6 and W=x, substitute these into the equation P=2W + 2L and solve for L:<BR>\n" );
document.write( "6x+6 = 2x + 2L\r<BR>\n" );
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document.write( "Subtract 2x from each side:<BR>\n" );
document.write( "6x+6 -2x = 2x-2x+2L<BR>\n" );
document.write( "4x+6 = 2L\r<BR>\n" );
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document.write( "Divide both sides by 2:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284x%29%2F2+%2B+6%2F2+=+%282L%29%2F2+ ALIGN=MIDDLE  ALT=\"%284x%29%2F2+%2B+6%2F2+=+%282L%29%2F2+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x+%2B+3+=+L ALIGN=MIDDLE  ALT=\"2x+%2B+3+=+L\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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