document.write( "Question 955462: Franco invested $4000 in money market funds. Part was invested at 14% interest, the rest at 11% interest. At the end of each year the fund company pays interest. After one year he earned $482 in simple interest. How much was invested at each interest rate? \n" ); document.write( "
Algebra.Com's Answer #583688 by macston(5194)\"\" \"About 
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F=part invested at 14%; E=part invested at 11%
\n" ); document.write( "F+E=$4000
\n" ); document.write( "E=$4000-F
\n" ); document.write( "0.11E+0.14F=$482 Substitute for E.
\n" ); document.write( "0.11($4000-F)+0.14F=$482.
\n" ); document.write( "$440-0.11F+0.14F=$482 Subtract $440 from each side.
\n" ); document.write( "0.03F=$42 Divide each side by 0.03.
\n" ); document.write( "F=$1400 ANSWER 1: $1400 was invested at 14%.
\n" ); document.write( "E=$4000-$1400=$2600 ANSWER 2: $2600 was invested at 11%
\n" ); document.write( "CHECK:
\n" ); document.write( "0.11E+0.14F=$482
\n" ); document.write( "0.11($2600)+0.14($1400)=$482
\n" ); document.write( "$286+$196=$482
\n" ); document.write( "$482=$482
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