document.write( "Question 955454: solve for solutions over the interval (0 deg, 360 deg)\r
\n" ); document.write( "\n" ); document.write( "4 cos^2 theta + 4 cos theta = 1\r
\n" ); document.write( "\n" ); document.write( "i believe the quadratic formula applies but am stuck.
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Algebra.Com's Answer #583687 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
solve for solutions over the interval (0 deg, 360 deg)
\n" ); document.write( "4 cos^2 theta + 4 cos theta - 1 = 0
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\n" ); document.write( "cos(t) = [-4 +- sqrt(16-4*4*-1)]/8 = [-4+-4sqrt(2)]/8
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\n" ); document.write( "cos(t) = [-4 + 4sqrt(2)]/8 = [-1+sqrt(2)]/2 = 0.2071
\n" ); document.write( "or
\n" ); document.write( "cos(t) [-1-sqrt(2)]/2 = -1.2071 (extraneous)
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\n" ); document.write( "t = arccos(0.2071) = 78.04 degrees or 281.96 degrees
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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