document.write( "Question 955314: Ann is four years younger than Maria. In three years, ann is two thirds Maria's age. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #583682 by macston(5194)![]() ![]() You can put this solution on YOUR website! A=Ann's age; M=Maria's age=A+4yrs \n" ); document.write( "A+3yrs=2/3(M+3yrs) Substitute for M \n" ); document.write( "A+3yrs=2/3(A+4yrs+3yrs) Multiply each side by 3. \n" ); document.write( "3A+9yrs=2A+14yrs Subtract 2A+9 from each side \n" ); document.write( "A=5yrs ANSWER 1: Ann is 5 years old. \n" ); document.write( "M=A+4yrs=5yrs+4yrs=9yrs Maria is 9 years old. \n" ); document.write( "CHECK: \n" ); document.write( "A+3yrs=2/3(M+3yrs) \n" ); document.write( "5yrs+3yrs=2/3(9yrs+3yrs) \n" ); document.write( "8yrs=2/3(12yrs) \n" ); document.write( "8yrs=8yrs \n" ); document.write( " \n" ); document.write( " |