document.write( "Question 955458: A money box contains only 20 cent coins and 50 cent coins. If there are 57 coins in the moneybox and their total value is $24.30, how many 20 cent coins and how many 50 cent coins are there?
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Algebra.Com's Answer #583673 by stanbon(75887) $\"\"$ $\"About$

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A money box contains only 20 cent coins and 50 cent coins. If there are 57 coins in the moneybox and their total value is $24.30, how many 20 cent coins and how many 50 cent coins are there?
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\n" ); document.write( "Equation:
\n" ); document.write( "Quantity:: t + f = 57 coins
\n" ); document.write( "Value:: 20t+50f = 2430 cents
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\n" ); document.write( "Simplify for elimination:
\n" ); document.write( "2t + 2f = 2*57
\n" ); document.write( "2t + 5f = 243
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\n" ); document.write( "Subtract and solve for \"f\":
\n" ); document.write( "3f = 129
\n" ); document.write( "f = 43 (# of 50 cent coins)
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\n" ); document.write( "t = 57-43 = 14 (# of 20 cent coins)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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