document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955449>Question 955449</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A child's block is in the shape of half a cylinder. (It has a picture and it's like and the arc thing, it looks like a semicirle to me tho). The block is 10cm wide, 5 cm high and 3.5 cm thick. Find the surface area. The answer is 35 + 42.5pi in. I don't get how to get to that answer. Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583668 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For 2 half circles(top+bottom)<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5B1%5D ALIGN=MIDDLE  ALT=\"A%5B1%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=%28pi%29r%5E2 ALIGN=MIDDLE  ALT=\"Area=%28pi%29r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "... <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5B1%5D ALIGN=MIDDLE  ALT=\"A%5B1%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28pi%29%285%5E2cm%5E2%29=25%28pi%29cm%5E2 ALIGN=MIDDLE  ALT=\"%28pi%29%285%5E2cm%5E2%29=25%28pi%29cm%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "For curved side(1/2 circumference*height)<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5B2%5D ALIGN=MIDDLE  ALT=\"A%5B2%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=%28pi%29r%2Ah ALIGN=MIDDLE  ALT=\"Area=%28pi%29r%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5B2%5D ALIGN=MIDDLE  ALT=\"A%5B2%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28pi%29%285cm%29%283.5cm%29=17.5%28pi%29cm%5E2 ALIGN=MIDDLE  ALT=\"%28pi%29%285cm%29%283.5cm%29=17.5%28pi%29cm%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5B1%5D%2BA%5B2%5D=42.5%28pi%29cm%5E2 ALIGN=MIDDLE  ALT=\"A%5B1%5D%2BA%5B2%5D=42.5%28pi%29cm%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "For flat side <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5B3%5D ALIGN=MIDDLE  ALT=\"A%5B3%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=height%2Adiameter ALIGN=MIDDLE  ALT=\"Area=height%2Adiameter\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5B3%5D ALIGN=MIDDLE  ALT=\"A%5B3%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283.5cm%29%2810cm%29=35cm%5E2 ALIGN=MIDDLE  ALT=\"%283.5cm%29%2810cm%29=35cm%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Total surface area=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=42.5%28pi%29cm%5E2%2B35cm%5E2 ALIGN=MIDDLE  ALT=\"42.5%28pi%29cm%5E2%2B35cm%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > I don't know where the inches came from. </SPAN>\n" );
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