document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955374>Question 955374</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the point (-8,-6) is on the terminal arm of angle A in standard position, then cos(A) is?\r<BR>\n" );
document.write( "\n" );
document.write( "a. -4/5<BR>\n" );
document.write( "b. -3/5<BR>\n" );
document.write( "c. 3/5<BR>\n" );
document.write( "d. 4/5\r<BR>\n" );
document.write( "\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583649 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the point (-8,-6) is on the terminal arm of angle A in standard position, then cos(A) is?<BR>\n" );
document.write( "----<BR>\n" );
document.write( "cos(A) = x/r = -8/sqrt[8^2+6^2] = -8/sqrt(100) = -8/10 = -4/5<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "-------------------------<BR>\n" );
document.write( " a. -4/5<BR>\n" );
document.write( " b. -3/5<BR>\n" );
document.write( " c. 3/5<BR>\n" );
document.write( " d. 4/5 <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );