document.write( "Question 955412: Given a committee of 8 women and 11 men, how many different ways are there to pick a female president, a male treasurer, and a secretary of either gender if one of the men, Pete, says that he cannot be the treasurer? Assume that none can hold more than one office \n" ); document.write( "

Algebra.Com's Answer #583641 by hemu_da(13) $\"\"$ $\"About$

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\n" ); document.write( "No of women = 8
\n" ); document.write( "No of men = 11
\n" ); document.write( "Total members =19
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\n" ); document.write( "1- No of ways selecting 1 woman for female president out of 8 = 8C1 = 8
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\n" ); document.write( "2- because one man Pete can not be a treasurer hence the treasurer will be select from remaining 10, i.e.-
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\n" ); document.write( " No of ways selecting 1 treasurer out of 10 = 10C1 = 10.
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\n" ); document.write( "3- Pete can be a secretary. because none can hold more then one office therefore selection will be done by choosing 1 person out of 7 women and 10 men i.e.-
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\n" ); document.write( "No of ways selecting 1 person out of 17 = 17C1 = 17\r
\n" ); document.write( "\n" ); document.write( "Total no of ways= 8*10*17 = 1380 .. .. ANS \n" ); document.write( "

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