document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955341>Question 955341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is nine more than twice another. If their sum is decreased by ten, the result is fourteen. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583639 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583639\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x and y are the numbers<BR>\n" );
document.write( "x=2y+9<BR>\n" );
document.write( "x+y=14+10<BR>\n" );
document.write( "x=24-y<BR>\n" );
document.write( "24-y=2y+9 Add y to each side<BR>\n" );
document.write( "24=3y+9 Subtract 9 from each side.<BR>\n" );
document.write( "15=3y Divide each side by 3.<BR>\n" );
document.write( "5=y ANSWER 1: One of the numbers is 5<BR>\n" );
document.write( "x=24-y=24-5=19 ANSWER 2: The other number is 19.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "x+y-10=14<BR>\n" );
document.write( "19+5-10=14<BR>\n" );
document.write( "24-10=14<BR>\n" );
document.write( "14=14 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );