document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955379>Question 955379</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 6 inches more than 4 times the width. The perimeter is 162 inches. Find the length and the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583631 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583631\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=width; L=length=4W+6in; P=perimeter=162in<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "162in=2(4W+6in+W) Divide each side by 2.<BR>\n" );
document.write( "81in=5W+6in Subtract 6in from each side.<BR>\n" );
document.write( "75in=5W Divide each side by 5<BR>\n" );
document.write( "15in=W ANSWER 1: The width is 15 inches.<BR>\n" );
document.write( "L=4W+6in=4(15in)+6in=60in+6in=66in ANSWER 2: The length is 66 inches.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "162in=2(66in+15in)<BR>\n" );
document.write( "162in=2(81in)<BR>\n" );
document.write( "162in=162in </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );