document.write( "Question 81495: Solve each of the following systems by substitution.\r
\n" ); document.write( "\n" ); document.write( "5x - 2y = -5
\n" ); document.write( "y - 5x = 3
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Algebra.Com's Answer #58362 by praseenakos@yahoo.com(507)\"\" \"About 
You can put this solution on YOUR website!
QUESTION:\r
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\n" ); document.write( "\n" ); document.write( "Solve each of the following systems by substitution.\r
\n" ); document.write( "\n" ); document.write( "5x - 2y = -5
\n" ); document.write( "y - 5x = 3\r
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\n" ); document.write( "\n" ); document.write( "ANSWER:\r
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\n" ); document.write( "\n" ); document.write( "5x - 2y = -5 ------------(1)\r
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\n" ); document.write( "\n" ); document.write( "y - 5x = 3 ---------------(2)\r
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\n" ); document.write( "\n" ); document.write( "Add 5x to both sides of the equation (2)\r
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\n" ); document.write( "\n" ); document.write( "==> y - 5x + 5x = 3 + 5x\r
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\n" ); document.write( "\n" ); document.write( "==> y = 3 + 5x --------------(3)\r
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\n" ); document.write( "\n" ); document.write( "Substitute this value of y, that is y = 3 + 5x in equation(1)\r
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\n" ); document.write( "\n" ); document.write( "==> 5x - 2(3 + 5x) = -5\r
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\n" ); document.write( "\n" ); document.write( "==> 5x - 2*3 - 2*5x = -5\r
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\n" ); document.write( "\n" ); document.write( "==> 5x - 6 - 10x = -5\r
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\n" ); document.write( "\n" ); document.write( "==> 5x - 10x - 6 = -5\r
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\n" ); document.write( "\n" ); document.write( "==> -5x - 6 = -5\r
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\n" ); document.write( "\n" ); document.write( "Add 6 to both sides of the equation....\r
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\n" ); document.write( "\n" ); document.write( "==> -5x - 6 + 6 = -5 + 6\r
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\n" ); document.write( "\n" ); document.write( "==> -5x = 1\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by -5\r
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\n" ); document.write( "\n" ); document.write( "==> -5x/-5 = 1/-5\r
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\n" ); document.write( "\n" ); document.write( "==> x = -1/5\r
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\n" ); document.write( "\n" ); document.write( "Now put the value of x in (3)\r
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\n" ); document.write( "\n" ); document.write( "==> y = 3 + 5(-1/5)\r
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\n" ); document.write( "\n" ); document.write( "==> y = 3 + (-1)\r
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\n" ); document.write( "\n" ); document.write( "==> y = 2\r
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\n" ); document.write( "\n" ); document.write( "So we have ,\r
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\n" ); document.write( "\n" ); document.write( "x = -1/5 and \r
\n" ); document.write( "\n" ); document.write( "y = 2\r
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\n" ); document.write( "\n" ); document.write( "To check your answer, substitute these values in the first equation then you will find it satisfies the equation.\r
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\n" ); document.write( "\n" ); document.write( "Hope you found the explanation useful...\r
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\n" ); document.write( "\n" ); document.write( "Regards.\r
\n" ); document.write( "\n" ); document.write( "Praseena.\r
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