document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81518>Question 81518</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, can someone help with the following?\r<BR>\n" );
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document.write( "P dollars is invested at annual interest rate R for 1 year.  If the interest is compounded semiannually, then the polynomial P (1+ r/2)squared represents the value of the investment after 1 year.  Rewrite this expression without parentheses.  Evaluate the polynomial if P=$200 and r=10%   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58359 by </B><A HREF=/tutors/aboutme.mpl?userid=dolly><B>dolly(163)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dolly><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given the value of investment after 1 year is :\r<BR>\n" );
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document.write( "V = P(1 + r/2 )^2\r<BR>\n" );
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document.write( "==> V = P (1 + r + r^2/4) [using (a+b)^2 = a^2 + 2ab + b^2]\r<BR>\n" );
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document.write( "==> V = P + Pr + Pr^2/4\r<BR>\n" );
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document.write( "This is the required polynomial.\r<BR>\n" );
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document.write( "When P = 200 and r = 0.1 then,\r<BR>\n" );
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document.write( "V = 200 + 200(0.1) + 200(0.1)^2/4\r<BR>\n" );
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document.write( "   = 200 + 20 + 0.5\r<BR>\n" );
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document.write( "   = 220.5\r<BR>\n" );
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document.write( "Thus the value of the investment of $200 after 1 year at 10% is $ 220.5\r<BR>\n" );
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document.write( " </SPAN>\n" );
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