document.write( "Question 955359: Table of Data includes:
\n" ); document.write( "Population in the United States as a function of time\r
\n" ); document.write( "\n" ); document.write( "x(years since 1920):{0,10,20,30,40,50,60,70,80,90}
\n" ); document.write( "y(Population in millions): {106,123.2,132.2,151.3,179.3,203.3,226.5,248.7,281.4,308.7}\r
\n" ); document.write( "\n" ); document.write( "Find:\r
\n" ); document.write( "\n" ); document.write( "1). Draw a scatter plot : Done already
\n" ); document.write( "2). Use calculator to find \"the line of best fit\" for this data. Show the equation.
\n" ); document.write( "I found approximately y=2.28x+93.41
\n" ); document.write( "3). What is the slope of the line? I know it is 2.28
\n" ); document.write( "What is the meaning in this application? (Give its units.)
\n" ); document.write( "I believe the meaning is to go up 2.28 and over one. In units I would say roughly twenty but I was hoping for better help in a translation of this answer. I believe I am incorrect.\r
\n" ); document.write( "\n" ); document.write( "4). By hand, develop an exponential model of the form A=Aoe^kt using the data from 1920 and 2000. Round the value of k to 4 decimal places.\r
\n" ); document.write( "\n" ); document.write( "I am unsure on how to do this.\r
\n" ); document.write( "\n" ); document.write( "5). Use your calculator to find \"exponential function of best fit\" for this data. Show the equation.\r
\n" ); document.write( "\n" ); document.write( "y=106.726(1.0124)^x\r
\n" ); document.write( "\n" ); document.write( "6). use function found in 5) to determine the annual percentage rate of growth of the United States\r
\n" ); document.write( "\n" ); document.write( "I assume 1.24%
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Algebra.Com's Answer #583585 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
1) OK
\n" ); document.write( "2) Yes, correct
\n" ); document.write( "3) Slope in this problem means it the change in population per year so the population was increase at roughly 2.3 million people per year since 1920.
\n" ); document.write( "4) You use two data points to solve for the two unknowns,
\n" ); document.write( "1920 -> 0-106
\n" ); document.write( "2000 -> 80-281.4
\n" ); document.write( "\"A=A%5B0%5De%5E%28kx%29\"
\n" ); document.write( "So when \"t=0\", \"A=106\"
\n" ); document.write( "\"106=A%5B0%5De%5E%280%29\"
\n" ); document.write( "\"A%5B0%5D=106\"
\n" ); document.write( "and
\n" ); document.write( "when \"x=80\", \"A=281.4\"
\n" ); document.write( "\"281.4=106e%5E%2880x%29\"
\n" ); document.write( "\"e%5E%2880t%29=2.654717\"
\n" ); document.write( "\"80k=ln%282.654717%29\"
\n" ); document.write( "\"k=ln%282.654717%29%2F80\"
\n" ); document.write( "\"k=0.0122\"
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\n" ); document.write( "\"y=106e%5E%280.0122x%29\"
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\n" ); document.write( "5) I get a slightly different answer using an online regression calculator
\n" ); document.write( "\"y=107.4367%281.0121%29%5Ex\"
\n" ); document.write( "6) Yes, that's correct, take your multiplier, subtract 1 and multiply by 100 to get the annual percentage growth rate.\r
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