document.write( "Question 81517: Hi! I always like to try to figure these out before I ask for help, so can you tell me if I am anwhere where I need to be on this one? Thanks!!!\r
\n" ); document.write( "\n" ); document.write( "Solve using the square root property:
\n" ); document.write( "2x2 – 3 = 15\r
\n" ); document.write( "\n" ); document.write( "2x^2=15\r
\n" ); document.write( "\n" ); document.write( "x=√15 or x=-√15\r
\n" ); document.write( "\n" ); document.write( "x=√3√5 or x=-√3√5
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #58357 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( " $\"2x%5E2-3+=+15\"$ Add 3 to both sides.
\n" ); document.write( " $\"2x%5E2+=+18\"$ Divide both sides by 2.
\n" ); document.write( " $\"x%5E2+=+9\"$ Take the square root of both sides.
\n" ); document.write( " $\"x+=+3\"$ or $\"x+=+-3\"$
\n" ); document.write( " \n" ); document.write( "

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