document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81520>Question 81520</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you graph x^2-12x+36=0  to estimate the solutions of the equations? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58355 by </B><A HREF=/tutors/aboutme.mpl?userid=dolly><B>dolly(163)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dolly><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The following shows the graph for y = x^2 - 12x + 36\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+20%2C+x%5E2-12x%2B36%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+20%2C+x%5E2-12x%2B36%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The solution to the equation x^2 - 12x + 36 = 0 are the points where the graph cuts the x axis.\r<BR>\n" );
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document.write( "In the above fig, we find that the graph touches the x axis at only one point namely 6.\r<BR>\n" );
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document.write( "Thus x = 6 is the only solution for the given graph.  </SPAN>\n" );
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