document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81521>Question 81521</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The distance required for a car to stop is directly proportional to the square of its velocity.  If a car can stop in 112.5 meters at 15 kilometers per hour, how many meters are needed to stop at 25 kilometers per hour. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58354 by </B><A HREF=/tutors/aboutme.mpl?userid=dolly><B>dolly(163)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dolly><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that the distance is directly proportional to to the square of velocity.<BR>\n" );
document.write( "Let 'd' be the distance and 'v' be the velocity.<BR>\n" );
document.write( "Then d = K v^2 where K is the constant of proportionality<BR>\n" );
document.write( "==>  112.5 = K (15)^2<BR>\n" );
document.write( "==>  112.5 = K * 225<BR>\n" );
document.write( "==>   112.5/225 = K<BR>\n" );
document.write( "==>   K = 0.5\r<BR>\n" );
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document.write( "Case(ii)\r<BR>\n" );
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document.write( "Given v = 25\r<BR>\n" );
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document.write( "So d = K*v^2<BR>\n" );
document.write( "     = 0.5 * (25)^2\r<BR>\n" );
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document.write( "     = 0.5 * 625\r<BR>\n" );
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document.write( "    = 312.5\r<BR>\n" );
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document.write( "So 312.5 meters are needed to stop at 25 Km/hr </SPAN>\n" );
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