document.write( "Question 81522: Match the equation with a graph. I do not know this at all
\n" ); document.write( "A y=-2/3x+1, B y=-3/2x+1 C y=2x-1 D y=1/2x-1.\r
\n" ); document.write( "\n" ); document.write( "What would a graph look like that matched one of these equations.
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Algebra.Com's Answer #58351 by mathdoc316(9)\"\" \"About 
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\n" ); document.write( "A y = -2/3 x + 1
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\n" ); document.write( " Here is what it would look like:
\n" ); document.write( " It slants sort of in this direction \ but much less steep than that
\n" ); document.write( " It crosses the y axis at one unit above the origin
\n" ); document.write( " The origin is where the two axes meet, the x and y axis, at (0,0).\r
\n" ); document.write( "\n" ); document.write( "B y = -3/2 x + 1
\n" ); document.write( " This slants more like this slope \
\n" ); document.write( " It also crosses the y axis at one unit above the origin
\n" ); document.write( " It has the points (2, -2) and (-2, 4) on it\r
\n" ); document.write( "\n" ); document.write( "C y = 2x - 1
\n" ); document.write( " This slopes steeply up to the right like this /
\n" ); document.write( " It crosses the y axis one unit below the origin
\n" ); document.write( " Each time x changes by 1, the y changes by 2
\n" ); document.write( " Some points on it are (0, -1) (1,1) (2,3) (3,5) (4,7) if the graph goes that far up\r
\n" ); document.write( "\n" ); document.write( "D I will let you figure this one out. Note the slope is less than one, but greater than 0, so its angle will be less than 45 degrees, and will slope upwards to the right\r
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