document.write( "Question 955209: How to solve x+y=4, -2x+3y=7 by substitution \n" ); document.write( "
Algebra.Com's Answer #583462 by macston(5194)\"\" \"About 
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x+y=4
\n" ); document.write( "x=4-y
\n" ); document.write( "-2x+3y=7 Substitute for x
\n" ); document.write( "-2(4-y)+3y=7
\n" ); document.write( "-8+2y+3y=7
\n" ); document.write( "-8+5y=7
\n" ); document.write( "5y=15
\n" ); document.write( "y=3 ANSWER 1:y=3
\n" ); document.write( "x+y=4
\n" ); document.write( "x+3=4
\n" ); document.write( "x=1 ANSWER 2:x=1
\n" ); document.write( "CHECK:
\n" ); document.write( "-2x+3y=7
\n" ); document.write( "-2(1)+3(3)=7
\n" ); document.write( "-2+9=7
\n" ); document.write( "7=7 \n" ); document.write( "
\n" );