document.write( "Question 955168: What is the smallest of 3 consecutive positive integers,if the product of the 2 smaller integers is 5 less than 5 times the largest integer? \n" ); document.write( "
Algebra.Com's Answer #583432 by macston(5194)\"\" \"About 
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Smallest integer=n; middle integer=n+1; largest integer=n+2
\n" ); document.write( "(n)(n+1)=5(n+2)-5
\n" ); document.write( "\"n%5E2%2Bn=5n%2B10-5\"
\n" ); document.write( "\"n%5E2%2Bn=5n%2B5\" Subtract (5n+5) from each side.
\n" ); document.write( "\"n%5E2-4n-5=0\"\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"an%5E2%2Bbn%2Bc=0\" (in our case \"1n%5E2%2B-4n%2B-5+=+0\") has the following solutons:
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\n" ); document.write( " \"n%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-4%29%5E2-4%2A1%2A-5=36\".
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\n" ); document.write( " Discriminant d=36 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--4%2B-sqrt%28+36+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"n%5B1%5D+=+%28-%28-4%29%2Bsqrt%28+36+%29%29%2F2%5C1+=+5\"
\n" ); document.write( " \"n%5B2%5D+=+%28-%28-4%29-sqrt%28+36+%29%29%2F2%5C1+=+-1\"
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\n" ); document.write( " Quadratic expression \"1n%5E2%2B-4n%2B-5\" can be factored:
\n" ); document.write( " \"1n%5E2%2B-4n%2B-5+=+1%28n-5%29%2A%28n--1%29\"
\n" ); document.write( " Again, the answer is: 5, -1.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-4%2Ax%2B-5+%29\"

\n" ); document.write( "\n" ); document.write( "n=5 ANSWER: The smallest integer is 5.
\n" ); document.write( "CHECK:
\n" ); document.write( "middle integer=n+1=5+1=6
\n" ); document.write( "largest integer=n+2=5+2=7
\n" ); document.write( "Product of two smaller is 5 less than 5 times larger:
\n" ); document.write( "5(6)=5(7)-5
\n" ); document.write( "30=35-5
\n" ); document.write( "30=30
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