document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955097>Question 955097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. The measure of one angle is 20 less then 1/3 of the other. Find the measures of both angles.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583397 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=one angle b=other angle=(1/3)a-20<BR>\n" );
document.write( "a+b=180 degrees Substitute for b<BR>\n" );
document.write( "a+((1/3)a-20)=180 degrees Add 20 to each side<BR>\n" );
document.write( "(4/3)a=200 degrees Multiply each side by 3/4<BR>\n" );
document.write( "a=150 degrees ANSWER 1: One angle measures 150 degrees.<BR>\n" );
document.write( "b=(1/3)a-20=(1/3)(150)-20=50-20=30 degrees ANSWER 2: The second angle is 30 degrees. </SPAN>\n" );
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