document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=955035>Question 955035</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bicyclist is riding at a speed of 18 miles per hour down a  long hill. The distance D she travels in feet can be modeled by d(t)=4t^2+18t, where t is the time in seconds. How long will it take her to reach the bottom of a 400 foot long hill?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583339 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583339\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A bicyclist is riding at a speed of 18 miles per hour down a long hill. The distance D she travels in feet can be modeled by d(t)=4t^2+18t, where t is the time in seconds. How long will it take her to reach the bottom of a 400 foot long hill? <BR>\n" );
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document.write( "Solve::<BR>\n" );
document.write( "4t^2 + 18t = 400<BR>\n" );
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document.write( "2t^2 +  9t - 200 = 0<BR>\n" );
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document.write( "(2t+25)(t-8) = 0<BR>\n" );
document.write( "Ans:  t = 8 seconds<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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