document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81490>Question 81490</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each of the following systems by addition. If a unique solution does not exist, state<BR>\n" );
document.write( "whether the system is inconsistent or dependent.\r<BR>\n" );
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document.write( "x + 5y = 10<BR>\n" );
document.write( "-2x - 10y = -20 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58332 by </B><A HREF=/tutors/aboutme.mpl?userid=jainenderkapoor><B>jainenderkapoor(61)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jainenderkapoor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jainenderkapoor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + 5y = 10<BR>\n" );
document.write( "-2x - 10y = -20\r<BR>\n" );
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document.write( "If I look at the equations carefully...<BR>\n" );
document.write( "I see that I can get the (2) equation by simply multiplying (1) by -2\r<BR>\n" );
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document.write( "These type of equations are called dependent equations, as they will have same solution. If we try to plot a graph for each of the equation.. we will get only one single line.. <BR>\n" );
document.write( "Please visit --  http://www.purplemath.com/modules/systlin2.htm   --  to see and learn more about system of linear equations.\r<BR>\n" );
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document.write( "Hope the solution is clear to you. In case you have any other doubt, you are welcome to contact me on jainenderkapoor@gmail.com  I am also available for Online Tutoring at very reasonable rates.\r<BR>\n" );
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document.write( "Jainender Kapoor </SPAN>\n" );
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