document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954934>Question 954934</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two planes which are 1905 miles apart, fly towards each other. their speed differ by 35 mph.If they pass each other in 3 hours what is the speed of each? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583307 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583307\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r=rate of slower plane; r+35mph=rate of faster plane<BR>\n" );
document.write( "1905mi/(r+r+35mph)=3 hrs<BR>\n" );
document.write( "1905mi/(2r+35mph)=3hrs Multiply each side by 2r+35mph.<BR>\n" );
document.write( "1905mi=3hr(2r+35mph)Divide each side by 3 hr.<BR>\n" );
document.write( "635mph=2r+35mph Subtract 35 mph from each side.<BR>\n" );
document.write( "600mph=2r Divide each side by 2.<BR>\n" );
document.write( "300mph=r ANSWER 1: The rate of the slower plane is 300 mph.<BR>\n" );
document.write( "r+35 mph=300mph+35mph=335 mph ANSWER 2: The faster plane traveled at 335 mph. </SPAN>\n" );
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