document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954938>Question 954938</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The speed of a stream is 6 mph. If a boat travels 90 miles downstream in the same time that it takes to travel 45 miles upstream, what is the speed of the boat in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583303 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583303\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> s=speed of boat in still water<BR>\n" );
document.write( "90mi/(s+6mph)=45mi/(s-6mph) Multiply each side by (s+6)(s-6)<BR>\n" );
document.write( "90mi(s-6mph)=45mi(s+6mph)<BR>\n" );
document.write( "90s-540=45s+270 Add 540 to each side.<BR>\n" );
document.write( "90s=45s+810 Subtract 45s from each side.<BR>\n" );
document.write( "45s=810 Divide each side by 45.<BR>\n" );
document.write( "s=18 ANSWER: The speed of the boat in still water is 18 mph<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "90mi/(18mph+6mph)=45 mi/(18mph-6mph)<BR>\n" );
document.write( "90 mi/24mph=45mi/12mph<BR>\n" );
document.write( "3.75 hours=3.75 mph </SPAN>\n" );
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