document.write( "Question 954957: the sun of the ages of 6 children born at intervals of 3 years each is 81. what is the age of the youngest ? \n" ); document.write( "
Algebra.Com's Answer #583298 by addingup(3677)\"\" \"About 
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Let's call the youngest a. The next is therefore a+3. And the one after that a+6:
\n" ); document.write( "a+a+3+a+6+a+9+a+12+a+15 = 81 Add on the left
\n" ); document.write( "6a+45= 81 subtract 45 on both sides
\n" ); document.write( "6a= 36 divide both sides by 6:
\n" ); document.write( "a= 6 The youngest child is 6.
\n" ); document.write( "Proof:
\n" ); document.write( "6+(6+3)+(6+6)+(6+9)+(6+12)+(6+15)= 6+9+12+15+18+21= 81 Correct.
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