document.write( "Question 954856: A man is 13 times as old as his son. In ten years he will be 3 times as old as his son will be then. How old is the son now? \n" ); document.write( "
Algebra.Com's Answer #583285 by amarjeeth123(570)![]() ![]() ![]() You can put this solution on YOUR website! Let the son's age be x. \n" ); document.write( "Then the father's age is 13x. \n" ); document.write( "In ten years their ages will be (x+10) and (13x+10). \n" ); document.write( "(13x+10)=3(x+10) \n" ); document.write( "13x+10=3x+30 \n" ); document.write( "10x=20 \n" ); document.write( "x=2 \n" ); document.write( "The son is 2 years old. \n" ); document.write( " |